A 0.5 kg object at 16°C is put into a beaker containing 2 kg of water at 25°C. By assuming that no heat is lost to the surrounding, calculate the final temperature of the water. (Specific heat capacity of object = 840J/kg °C, specific heat capacity of water = 4200J/kg°C)
HELP ME! :(
1 answer
.5 (840)(T-16) = 2(4200)(25-T)
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