What is the specific heat of a metal if 24.8 g absorbs 65.7 cal of energy and the temperature rises from 20.2 degrees celsius to 24.5 degrees celsius?

Answer 1

q = mass x specific heat x (Tfinal-Tinitial)
65.7 = 24.8 x sp.h. x (24.5-20.3)
Solve for sp.h.

Answer 2

11.4

Answer 3

q = mass x specific heat x (Tfinal-Tinitial) 65.7 = 24.8 x s.h. x (24.5-20.2)
0.616