correct
If your x's drop out and you end up with a false statement, such as our 6 = 7, then there is NO solution
if, however, the x's drop out and you end up with a true statement, there would have been an infinite number of solutions.
What is the solution to
x+5+x+1+x=3(x+2)+1
1)x=0
2)x=3
3)no solution
4) infinite
I got #3 no solution
x+5+x+1+x=3(x+2)+1
x+5+x+1+x=3x+6+1
3x+6=3x+7
-3x -3x
6=7 so no solution
Is this correct?
Thanks for checking over my work.
2 answers
OK.
Thanks for the added information explaining how the answer could have been different.
Thank you for your help!
Thanks for the added information explaining how the answer could have been different.
Thank you for your help!