Asked by anonymous

what is the solution of the system of equations.

2x+2y+3z=-6
3x+5y+4z=3
2x+3y+4z=-10
Answered by Steve
(x,y,z) = (5,4,-8)
Answered by anonymous
is there away to show your work
Answered by Steve
sure. One way is to do elimination by adding and subtracting multiples of one equation from another.

subtract 2*second from 3*first:
6x+6y+9z = -18
6x+10y+8z = 6
-----------------
-4y + z = -24

subtract first from third
-y - z = 4

now add those two to get

-5y = -20
y=4
so, z=-8 and x=5
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