what is the solution of the system of equations.

2x+2y+3z=-6
3x+5y+4z=3
2x+3y+4z=-10

3 answers

(x,y,z) = (5,4,-8)
is there away to show your work
sure. One way is to do elimination by adding and subtracting multiples of one equation from another.

subtract 2*second from 3*first:
6x+6y+9z = -18
6x+10y+8z = 6
-----------------
-4y + z = -24

subtract first from third
-y - z = 4

now add those two to get

-5y = -20
y=4
so, z=-8 and x=5