What is the solubility of Ag2CrO4 in 0.100 M AgNO3? Ksp = 1.12 x 10-12

Answer 1

...............Ag2CrO4(s) ---> 2Ag^+ + CrO4^2-
I...................solid.................0..............0
C.................solid-x...............2x............x
E..................solid..................2x............x

...............AgNO3(s)...............Ag^+ + NO3^-
I...............0.100.......................0............0
C..............-0.100....................0.100......0.100
E................0.........................0.100.........0.100
Ksp Ag2CrO4 = (Ag^+)^2(CrO4^2-) = 1.12E-12
From above you know (Ag^+) = 2x from Ag2CrO4 + 0.100 from AgNO3 for a total of 2x + 0.100. Plug that in for (Ag^+) in Ksp expression.
You know (CrO4^2-) = x.
Plug those into Ksp for Ag2CrO4 expression and solve for x = solubility Ag2CrO4 in this solution. Post your work if you get stuck.