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We add excess Na2CrO4 solution to 68.0 mL of a solution of silver nitrate (AgNO3) to form insoluble solid Ag2CrO4. When it has been dried and weighed, the mass of Ag2CrO4 is found to be 0.270 grams. What is the molarity of the AgNO3 solution? Answer in units of M

2 answers

Na2CrO4 + 2AgNO3 ==> Ag2CrO4
mols Ag2CrO4 = grams/molar mass = ?
mols AgNO3 = 1/2 that from the coefficients in the balanced equation.
M AgNO3 = mols AgNO3/L AgNO3.
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