smallest number ---- x
middle number ------ x+1
larger number --------x+2
x + x+1 = 4(x+2) - 177
2x+1 = 4x+8-117
-2x = -110
x = 55
the smallest is 55
What is the smallest of three consecutive integers if
the sum of the smaller two integers is equal to 177 less than four times the largest?
Note: Consecutive integers are integers that come one after the other. For example: -3, -2 and -1 or 14, 15 and 16. Therefore, if the first number is x, the second is x + 1 and the third is x + 2. Each time we add one to the previous integer to get the next consecutive integer.
7 answers
i tried 55 and i got it wrong
Reiny me and madison don't understand this we got it wrong when we tried 55
I even double checked and its wrong i don't know why?
Amy/Brianna/ Joshua/Madison -- please use the same name for your posts.
Correction of subject
According to my solution the 3 numbers are
55, 56, and 57
sum of the first two = 55+56 = 111
117 less than 4 times the larger = 4(57) - 117
= 111
Well, what do you know, it works
55, 56, and 57
sum of the first two = 55+56 = 111
117 less than 4 times the larger = 4(57) - 117
= 111
Well, what do you know, it works