What is the phase difference between input and output voltages?

Question

supply voltages = ±12V
amplitude =100mV
frequency = 500Hz
r1 = 1 kΩ
r2 = 27 kΩ
vcc = 12v
vee = 12v

Av = vout/vin = ?
Av (db) = 20 log(vout/vin) = ?
𝑃ℎ𝑎𝑠𝑒 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 (𝜑) = ?

Answer 1

We need to know the circuit configuration to determine the phase difference between input and output voltages. Without this information, we cannot calculate the phase difference.

Answer 2

vin = 100mVpk, 500 hz
r1 = 1 kΩ
r2 = 27 kΩ
vcc = 12v
vee = 12v

Av = vout/vin = ?
Av (db) = 20 log(vout/vin) = ?
𝑃ℎ𝑎𝑠𝑒 𝐷𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 (𝜑) = ?

Answer 3

The given circuit is an inverting amplifier configuration.

Av = -R2/R1 = -27kΩ/1kΩ = -27

Av (db) = 20 log(|Av|) = 20 log(27) = 30.6 dB

The phase difference between the input and output voltages in an inverting amplifier is 180 degrees or π radians. Therefore, the phase difference is 𝜑 = π.