What is the pH of a one liter auqueous solution to which has been added 0.2 moles of acetic acid (CH3COOH)?

Answer 1

CH3COOH + H2O = CH3COO- + H3O+
Acid acetic is a weak acid so not all of it will dissociate. The constant for acid acetic is 1.8 . 10^-5
therefore 1.8x10^-5=(x^2)/(0.2-x)
x is the amount that disociated
solve the equation and x is 1.88x10^-3
pH=-log(pH)=-log(1.88x10^-3)=2.72

Answer 2

thank you so very much this helped so much!!!!!