mmols HCl = 11.1 x 0.278 = 3.0858
mmoles NH3 = 70.9 x 0.13 = 9.217
..........HCl + NH3 ==> NH4Cl
initi...3.0858..9.217....0
change-3.0858..-3.0858...+3.0858
equil....0.......6.131....3.0858
From the ICE chart you can see that you have a solution of NH3 (a weak base) and its salt (NH4Cl) which makes a buffer.
Use the Henderson-Hasselbalch equation to solve for pH. Check my arithmetic.
What is the Ph for the solution made from 11.10mL of 0.278M HCL solution mixed with 70.90mL of 0.1300M ammonia solution? The pKa for NH4 is 9.241.
1 answer