surely you have the formula for the period of a pendulum of length L (and small amplitude):
T = 2π √(L/g)
Now just plug in your numbers.
What is the period, in seconds, of a simple pendulum of length 3 meters?
Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places
Please help! A step by step would with the answer would be helpful!
6 answers
the answer is 3.48
the guy up top stupid the answer is wrong
D man is correct, it is 3.48.
3.48 just like what D man said
4.49
1 answer