WHAT IS THE PERIMETER OF A SQUARE WHOSE VERTICLES ARE A(-4,-3), B(-5,1), C(-1,2), AND D(0,-2)?

Answer 1

Use the formula for distance between two points between the points of each of the four sides, and sum the distances.

Distance between two points P1(x1,y1) and P2(x2,y2):
D=sqrt((x2-x1)^2+(y2-y1)^2)

P.S.
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