WHAT IS THE PERIMETER OF A SQUARE WHOSE VERTICLES ARE A(-4,-3), B(-5,1), C(-1,2), AND D(0,-2)?

Answer 1

AB=sqrt(((-5)-(-4))^2+(1-(-3))^2)=
sqrt((-1)^2+4^2)=sqrt(17)

The perimeter=4*AB

Answer 2

THANK YOU

Answer 3

You're welcome.

Answer 4

P=4.(17)^1/2