You must first determine the theoretical yield.
mols W2O3 = grams/molar mass = ?
Use the coefficients to convert mols W2O3 to mols W.
Convert mols W grams. g = mols x atomic mass. This is the theoretical yield (TY). The actual yield in the problem is 147.8g (AY).
%W = (AY/TY)*100 = ?
What is the percent yield for a reaction when 166.3 grams of W2O3 combines with Carbon Monoxide but only produces 147.8 grams of W? chemical equation is W2O3+3CO------>2W+3CO2
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