The reaction of 8 grams of fluorine with excess

chlorine produced 6.4 grams of ClF3. What
percent yield of ClF3 was obtained?
Answer in units of %

2 answers

Cl2 + 3F2 ==> 2ClF3

mols F2 = g/molar mass = ?
Using the coefficients in the balanced equation, convert mols F2 to mols Cl
F3.
Now convert mols ClF3 to grams. g = mols x molar mass = ? This is the theoretical yield (TY) assuming 100% of the product is formed.The actual yield (AY) in the problem is 6.4 g.

Then % yield = [(AY)/(TY)]*100
Post your work if you get stuck.
Got it! Thank you :)
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