Ask a New Question

what is the number of moles of nonvolatile nonelectrolyte dissolved in 3.5 kg of water when the solution boils at 101.86 degrees C

1 answer

delta T = Kb*m
delta T = 101.86 - normal boiling point.
Substitute and solve for m = molality.

m = mols/Kg solvent. You know kg solvent and m, solve for mols.

Ask a New Question or answer this question.

Similar Questions

An unknown nonelectrolyte and nonvolatile compound is dissolved in enough pure water to make 229 ml of solution. The vapour
1. 3 answers
When 3.75 g of a nonelectrolyte solute is dissolved in 405 mL of water at 25 °C, the resulting solution exerts an osmotic
1. 1 answer
When 3.78 g of nonvolatile solute is dissolved in 300.0 g of water, the freezing point depression is 0.646 o C. Calculate the
1. 0 answers
If 0.380 mol of a nonvolatile nonelectrolyte are dissolved in 3.00 mol of water, what is the vapor pressure P(H2O) of the
1. 1 answer

more similar questions