What is the moment of inertia of an object that rolls without slipping down a 2.00-m-high incline starting from rest, and has a final velocity of 6.00 m/s? Express the moment of inertia as a multiple of MR2, where M is the mass of the object and R is its radius.

Answer 1

PE=KE=KE(transl) + KE(rot).

mgh = mv²/2 + I ω²/2=
= mv²/2 + I v²/2R².

I= (2R²/v²)(mgh- mv²/2)=
=mR²(2gh/v² -1) =
= mR²(2•9.8•2/36 -1)=
=mR²(1.09-1)=0.09 mR²

Answer 2

The answer's actually 12.