What is the molarity of ZnCl2 that forms when 30.0g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 285 mL . (please explain step by step I have no clue!)

Question

Zn(s) + CuCl2(aq) --> ZnCl2(aq)+ Cu(s)

Answer 1

From the equation 1 mole of Zn(s) gives 1 mole of ZnCl2(aq)

Number of moles of Zn is mass/molar mass of Zn
30.0 g /65.39 g mole^-1
=0.4588 mole

so 0.4588 mole ZnCl2 is formed (because 1 mole of Zn(s) gives 1 mole of ZnCl2(aq))

which is in 285 ml final volume

molarity is moles/volume (in L)

molarity =
0.4588 mole/0.285 L

Answer 2

l.64

Answer 3

the answer is approximately 1.6098 M