What is the molarity of ZnCl2(aq) that forms when 15.4 g of zinc completely reacts with CuCl2(aq) according to the following reaction? (Assume a final volume of 175 mL.)

Question

Zn(s) + CuCl2(aq) --> ZnCl2(aq) + Cu(s)

I got the moles of Zn but don't know what to do with it

thanks

Answer 1

moles Zn = 15.4 g Zn/atomic mass Zn.
Convert moles Zn to moles ZnCl2 using the coefficients in the balance equation.
Then M ZnCl2 = moles ZnCl2/L soln.

Answer 2

Thanks!