What is the molarity of nitrate ions in a solution containing 2.20 mg of Mg(NO3)2 dissolved in 7.35 L of water?

Answer 1

2.20 x 10^-3g *(1mole/148.3 g of Mg(NO3)2)= moles of Mg(NO3)2

moles of Mg(NO3)2 *(2 moles of NO3/1 mole of Mg(NO3)2))= moles of NO3

moles of NO3/7.35L=molarity

Answer 2

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