What is the molarity of dilute NaOH made from an original molarity of concentrated NaOH of 6.0 M, a volume of concentrated NaOH of 5.0 mL, and the final volume of diluted NaOH of 250 mL

Answer 1

To find the molarity of the dilute NaOH, we can use the dilution formula:

M1V1 = M2V2

Where:
M1 = initial molarity of concentrated NaOH = 6.0 M
V1 = initial volume of concentrated NaOH = 5.0 mL = 0.005 L (since 1 mL = 0.001 L)
M2 = final molarity of dilute NaOH (to be determined)
V2 = final volume of diluted NaOH = 250 mL = 0.25 L (since 1 mL = 0.001 L)

Substituting the given values into the formula:

(6.0 M)(0.005 L) = M2(0.25 L)

0.03 mol = 0.25 M2

Now, solve for M2:

M2 = 0.03 mol / 0.25 L
= 0.12 M

Therefore, the molarity of the dilute NaOH is 0.12 M.