To find the molarity of the dilute NaOH solution, we can use the dilution equation:
M₁V₁ = M₂V₂
Where:
M₁ = Molarity of the stock NaOH solution = 6.0 M
V₁ = Volume of the stock NaOH solution = 5 mL
M₂ = Molarity of the dilute NaOH solution (what we're trying to find)
V₂ = Final volume of the diluted NaOH solution = 250 mL
Substituting the given values into the equation:
6.0 M × 5 mL = M₂ × 250 mL
To solve for M₂, we divide both sides by 250 mL:
6.0 M × 5 mL ÷ 250 mL = M₂
M₂ = 0.12 M
Therefore, the molarity of the dilute NaOH solution is 0.12 M.
Molarity of dilute NaOH made if the stock NaOH molarity was 6.0 M at 5 mL and the final volume of diluted NaOH was 250 mL
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