What is the molar mass of a gas if 142g of the gas occupies a volume of 45.1 L at 28.4C and 94.6 kPa?

1 answer

To calculate the molar mass of the gas, we first need to convert the given values to appropriate units.

Using the ideal gas law equation:

PV = nRT

Where:
P = pressure in atm (94.6 kPa = 0.935 atm)
V = volume in L (45.1 L)
n = moles
R = gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin (28.4 + 273.15 = 301.55 K)

From the given information, we can rearrange the equation to solve for moles:

n = PV / RT
n = (0.935 atm) * (45.1 L) / (0.0821 L.atm/mol.K * 301.55 K)
n = 1.748 moles

Now, we can calculate the molar mass of the gas:

Molar mass = mass / moles
Molar mass = 142 g / 1.748 mol
Molar mass = 81.19 g/mol

Therefore, the molar mass of the gas is 81.19 g/mol.