2NaOH + H2SO4 ==> 2H2O + Na2SO4
mols NaOH = grams/molar mass = 0.644/40 = approx 0.016 but you need a better answer than this estimate.
mols H2SO4 = 1/2 mols NaOH (Look at the coefficients in the equation)= 0.008.
M H2SO4 = mols/L. You know mols and you know L, solve for M.
The point of this problem is that is doesn't matter a whit how much water you had in the NaOH, it's the mols NaOH that count and that is determined by the grams.
What is the molar concentration of a solution of sulfuric acid, H2SO4, if 4.64 mL react completely with 0.644 g of NaOH which was dissolved in 200 mL of water?
Hint given in feedback
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