Consider the reaction of sulfuric acid, H2SO4, with sodium hydroxide, NaOH.
H2SO4(aq) + 2 NaOH(aq) -> 2H2O(l) + Na2SO4(aq).
Suppose a beaker contains 35.0mL of 0.175M H2SO4. How many moles of NaOH are needed to react completely with sulfuric acid?
Thank you
1 answer
You have 0.0350 L x 0.175M = about 0.006125 mols H2SO4. It will take 2x that for mols NaOH