Educated deduction would be wise.
Tb-100C=Kb*Kions*molality
Now, Kb you have
Tb you have
Kions: 2 because in KCl it breaks up into two ion particales, K+, and Cl-
molality you are solving for.
Some texts use for Kions other symbols, check your text.
What is the molality of a solution of water and KCl if the boiling point of the solution is 103.07°C? (K subscript b equals 0.512 degrees C/m solution; KCl is an ionic compound right parenthesis
A: .300
B: .600
C: 3.00
D: 6.00
I'm really confused as to how to solve this, and can't make an educated guess, so any advice or help would be appreciated.
4 answers
As Bob P points out, Kion may be called the van't Hoff factor, i and for KCl it is 2.
1. b
2. a
3. b
4. c
100%
2. a
3. b
4. c
100%
hlsml is correct! 100%