delta x*delta p = h/4*pi where delta p = mv
v = 121.8 km/s. Convert to m/s so
delta p = mdelta v = 9.11E-31g*121.8 km/s x (1000 m/km) = ? and substitute into
delta x = 6.626E-31/4*3.1416*delta p
Post your work if you get stuck.
What is the minimum uncertainty in the position of an electron, in Angstroms, if its uncertainty in velocity is known to be 121.8 km/s
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