What is the minimal sample size needed for a 99% confidence interval to have a maximal margin of error of 0.06 if there is no preliminary estimate for p?

Answer 1

Formula to find sample size:
n = [(z-value)^2 * p * q]/E^2
... where n = sample size, z-value is found using a z-table for 99% confidence (which is 2.58), p = .5 (when no value is stated in the problem), q = 1 - p, ^2 means squared, * means to multiply, and E = 0.06

Plug values into the formula and calculate n.

I hope this will help get you started.

Answer 2

301