what is the maximum torque on a rectangular coil 5 cm x 12 cm and with 600 turns when carrying a current of 0.0700A in a uniform field with magnitude 0.300T?
2 answers
Give me and plz.
torque=nBIA
=600*10^-5*0.1*5*12*10^-4
=3.6*10^-6 ANSWER
=600*10^-5*0.1*5*12*10^-4
=3.6*10^-6 ANSWER
1 answer