A square coil with 30 turns has sides that are 18 cm long. When it is placed in a 0.31-T magnetic field, a maximum torque of 0.60 N⋅m is exerted on the coil. What is the current in the coil?

2 answers

|torque|=NBAIsina
Here A is area and sina=1 (a=90degree)
T=NBAI
I=T/NBA
I=0.6/30*0.31*(0.18)^2
I=1.99A