V^2 = Vo^2 + 2g*h = 0 at max. ht.
40^2 - 19.6*h = 0
19.6h = 1600
h = 81.6 m.
What is the maximum height achieved if a 0.800 kg mass is thrown straight upward with an initial speed of 40.0 m·s–1? Ignore the effect of air resistance.
1 answer
3 answers