What is the mass of 50.0 L of O2(g) at STP?

Question

O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters.
1.5625 × 22.4 = 35 liters.

Answer 1

do your calculations make sense to you?

you divided the volume of gas by the molar mass ... to get what?

you know the volume (50 L) , and the volume a mole occupies (22.4 L)

so you can find the moles , and use the molar mass to find the total mass

Answer 2

32 g/mol / 22.4 =1.42g/mol

Answer 3

if one mole occupies 22.4 L , how many moles can fit in 50.0 L?

what is the mass of these moles?

Answer 4

25.6

Answer 5

At STP => moles O2 = (50L)/(22.4L/mole) = 2.232 moles O2
2.232 moles O2 = (2.232 mole O2)(32 g/mole) = 71.429 grams O2