what is the mass density of mercury is 13.6g/cm^3. A cylinder of mercury has a diameter of 1 cm and a height of 76cm. what would the height of the cylinder of the water having a diameter of 1 cm and a mass equal to the mass of the mercury cylinder?

Answer 1

The mass of the mercury in the cylinder can be calculated by multiplying density x volume. Volume of a cylinder with radius (r) and height (h) is (πr^2)h. Remember radius is 1/2 diameter. So, mass of mercury = (13.6 g/cm^3) x ((π(0.5cm)^2)76cm = 59.67 g.

The height of a 1 cm diameter cylinder holding 59.67 g water can be found using the same equation for volume of a cylinder, assuming the density of water is 1g/cm^3, volume = (πr^2)h. 59.67g water = 59.67cm^3 = (π(0.5^2))h. Solving for h shows height is 76 cm.

Answer 2

My apologies... I neglected to multiply out the density of mercury, which yields 811.79g mercury. Solving for h then shows that water cylinder is 1033.6 cm.

(13.6 g/cm^3)((π(0.5cm)^2)76cm) = (π(0.5^2))h