Asked by Suzanne
The density of liquid mercury is 13.5 g/cm cube. What mass of mercury (in kg) is required to fill a hollow cylinder having an inner diameter of 2.00 cm to height of 25.0 cm?
Answers
Answered by
Dr Russ
Calculate the volume of the cylinder.
(pi)r^2h
3.142 x 1.0 cm^2 x 25.0 cm = approx 75 cm^3
(but calcutae the exact value)
mass = volume x density
mass = 75 cm^3 x 13.5 g cm^3 = approx 1000 g
(but calcutae the exact value)
or approximately 1 kg
(pi)r^2h
3.142 x 1.0 cm^2 x 25.0 cm = approx 75 cm^3
(but calcutae the exact value)
mass = volume x density
mass = 75 cm^3 x 13.5 g cm^3 = approx 1000 g
(but calcutae the exact value)
or approximately 1 kg
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