acceleration=changevelocity/time=5.8/2.8 m/s^2
d= 1/2 a t^2
What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 5.8 m/s when going down a slope for 2.8 s? How far does the skier travel in this time?
2 answers
13.645
1 answer