(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 10.5 m/s when going down a slope for 3.18 s? (b) How far does the skier travel in this time?

Answer 1

a. a = 10.5/3.18 = 3.3 m/s^2.

b. d = 0.5a*t^2 = 0.5*3.3*3.18^2 = 16.7 m.