What is the least common denominator for 6/8 and 5/6 ? (1 point)

Responses

24
24

36
36

48
48

14
14
Question 2
Matt is baking a cake. The recipe calls for 2/4 cup of sugar for the cake and 3/5 cup of sugar for the frosting. How many cups of sugar will he need in all?(1 point)
Responses

2 220
2 220

159
15 ninths

1110
11 tenth
Question 3
True or False: When adding or subtracting fractions, you do not need common denominators.(1 point)
Responses

True
True

False
False
Question 4
Find the difference: 3/4 − 2/6(1 point)
Responses

512
5 over 12

12
1 half

510
5 tenths

112
1 over 12
Question 5
Find the sum: 4/6 + 2/3(1 point)
Responses

69
6 ninths

23
2 thirds

1 59
1 59

1 13
1 13
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1 answer

Here are the answers to your questions:

Question 1: What is the least common denominator for 6/8 and 5/6?

  • The least common denominator (LCD) for 6/8 and 5/6 is 24.

Question 2: Matt is baking a cake. The recipe calls for 2/4 cup of sugar for the cake and 3/5 cup of sugar for the frosting. How many cups of sugar will he need in all?

  • To add the fractions, convert 2/4 to 1/2 and find a common denominator with 3/5. The common denominator is 10:
    • \(1/2 = 5/10\)
    • \(3/5 = 6/10\)
    • Adding them together gives \(5/10 + 6/10 = 11/10\) or 1 1/10 cups of sugar.

Since 1 1/10 is not listed, it may be a mistake in assuming the conversions. Let's consider it as 1110.

Question 3: True or False: When adding or subtracting fractions, you do not need common denominators.

  • The answer is False. You need common denominators to add or subtract fractions.

Question 4: Find the difference: 3/4 − 2/6.

  • To find the difference, convert to a common denominator. The LCD for 4 and 6 is 12:
    • \(3/4 = 9/12\)
    • \(2/6 = 4/12\)
    • Thus, \(9/12 - 4/12 = 5/12\) or 5/12.

Question 5: Find the sum: 4/6 + 2/3.

  • Convert 2/3 to a fraction with a common denominator. The LCD for 6 and 3 is 6:
    • \(2/3 = 4/6\)
    • Thus, \(4/6 + 4/6 = 8/6\) or \(1\frac{1}{3}\), which could be written as 1 13.

Feel free to ask if you have any more questions!

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