x/(x-3)-4-(2x-5)/(x+2)
If the problem is this:
x/(x - 3) - 4 - (3x - 5)/(x + 2)
...find a common denominator to start.
The common denominator is (x - 3)(x + 2), then convert each term using the common denominator.
Here's a start:
[x(x + 2)/(x - 3)(x + 2)] - [4(x - 3)(x + 2)]/(x - 3)(x + 2) - [(2x - 5)(x - 3)]/(x - 3)(x + 2) =
I'll let you take it from here. Remember to use the distributive property to distribute the negative!
I hope this will help and is what you were asking.
One correction!
I meant to type this for the problem:
x/(x - 3) - 4 - (2x - 5)/(x + 2)
The rest is OK. Sorry for any confusion!
but when I do this I get
x^2+2x-4x^2+4x+24-2x^2+x+15
solving this I get
(-5x^2+7x+39)/(x-3)(x+2)
The answer in the book however says
-(5x^2-17x-9)/(x-3)(x+2)
so I don't know what I am doing wrong, can you take me step by step through the problem. I have a lot of problems, but I think once I understand what I am doing wrong with this one I can get the rest.
The top should be this:
x^2 + 2x - 4x^2 + 4x + 24 - 2x^2 + 11x - 15
Combining like terms:
-5x^2 + 17x + 9
Factoring out the negative gives this:
-(5x^2 - 17x - 9)
This should help you see the answer given:
-(5x^2-17x-9)/(x-3)(x+2)
I hope this helps. Watch those negative signs because they can be tricky on these types of problems!
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