To find the least common denominator (LCD) of the given rational expressions in the subtraction \( \frac{x^2 + 2x}{x^2 + 7x - 8} - \frac{x}{x - 1} \), we need to factor each denominator.
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Factor \( x^2 + 7x - 8 \):
- We need to find two numbers that multiply to \(-8\) and add to \(7\). These numbers are \(8\) and \(-1\).
- Therefore, we can factor it as: \[ x^2 + 7x - 8 = (x + 8)(x - 1) \]
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The second denominator: \( x - 1 \) is already factored.
Now, we can determine the LCD. The denominators we have after factoring are:
- \( (x + 8)(x - 1) \) from \( \frac{x^2 + 2x}{x^2 + 7x - 8} \)
- \( x - 1 \) from \( \frac{x}{x - 1} \)
The LCD will be:
- The highest power of each factor present in the denominators. Here, we have:
- The factor \( x + 8 \) once.
- The factor \( x - 1 \) once, since it's common in both and doesn't need a higher power.
Thus, the LCD in its factored form will be: \[ (x - 1)(x + 8) \]
Therefore, the correct response is: \((x - 1)(x + 8)\)