I wonder if HCl is a solid or (aq). I don't know what HI2 is; I suspect that is a typo and should be 2HI. That equation isn't balanced as is. If as shown, then
Kc = 1/(Cl2)(HI)^2
What is the Keq of Cl2(aq) + 2HI2(g) -> I2(s) + 2HCl(s)
Solid is not included in the Keq expression, so what would Keq be?
Thanks in advance.
5 answers
There are 3 mols on each side. I made the question up, so I think HCl was supposed to be a gas.
I was just wondering if it would be Keq = 0/(Cl2)(HI)^2 or Keq= 1/(Cl2)(HI)^2. Thanks for clearing it up.
I was just wondering if it would be Keq = 0/(Cl2)(HI)^2 or Keq= 1/(Cl2)(HI)^2. Thanks for clearing it up.
No, Keq can't be zero on top. By definition, the activity of a solid is 1; therefore, 1 goes on top.
For the balancing, you do not balance total moles to equal total moles. You DO balance moles (or atoms) of individual elements. So a balanced equation could be
Cl2(aq) + 2HI(g) ==>I2(s) + 2HCl(s)
For the balancing, you do not balance total moles to equal total moles. You DO balance moles (or atoms) of individual elements. So a balanced equation could be
Cl2(aq) + 2HI(g) ==>I2(s) + 2HCl(s)
Whoops, forgot the rules to balancing an equation for a second, thanks! :)
Is the activity of pure liquids, 1, as well?
Is the activity of pure liquids, 1, as well?
Yes, the activity of a pure liquid is 1. The activity of a pure solid is 1.
1 answer