Substitute t = Log(x)/7
Integral is then proportional to:
Integral of dx/[x^2 + 13 x + 36] =
Integral of dx/[(x+4)(x+9)]
1/[(x+4)(x+9)] = A/(x+4) + B/(x+9)
Multiply both sides by x+4 and take limit x to -4:
1/5 = A
Multiply both sides by x+9 and take limit x to -9:
1/5 = A
-1/5 = B
What is the integral of
7e^(7t)
Divided By
e^14t+13e^7t+36
Using partial fractions
4 answers
Thank you so much.
I've reached the last step of
(7/5) ln((x+4)/(x+9)
But how do I substitute the variable 't' back in?
(7/5) ln((x+4)/(x+9)
But how do I substitute the variable 't' back in?
t = Log(x)/7 ---->
x = exp(7 t)
x = exp(7 t)