Question

what is the four digit number which satisfies these conditions;
The last digit is twice the first digit.
The second digit is twice the third digit.
The sum of the first and last digits is twice the third digit.

Answer 1

a b c d

d = 2 a

b = 2 c

a+d = 2 c

----------------------
a = 2 c - d = 2 c - 2 a
so
3 a = 2 c
hmmmm
if c is 1, nope
need common multiple for integer like
3 a = 6
2 c = 6
looks like a = 2 and c = 3
so far:
2 b 3 d
but d = 2 a
2 b 3 4
b = 2 c so
2 6 3 4

2634

Answer 2

thank you verymuch. But how 3a=6?

Answer 3

I needed a common multiple of 2 and 3
that is 6
we are not doing fractions here, just integers

Answer 4

ok thank you. God blss you