what is the four digit number which satisfies these conditions;

The last digit is twice the first digit.
The second digit is twice the third digit.
The sum of the first and last digits is twice the third digit.

4 answers

a b c d

d = 2 a

b = 2 c

a+d = 2 c

----------------------
a = 2 c - d = 2 c - 2 a
so
3 a = 2 c
hmmmm
if c is 1, nope
need common multiple for integer like
3 a = 6
2 c = 6
looks like a = 2 and c = 3
so far:
2 b 3 d
but d = 2 a
2 b 3 4
b = 2 c so
2 6 3 4

2634
thank you verymuch. But how 3a=6?
I needed a common multiple of 2 and 3
that is 6
we are not doing fractions here, just integers
ok thank you. God blss you