What is the final temperature and physical state of water when 250 grams of water at 85 degrees C is added to 80.0 grams of ice at -15 degree C?
Is the physical state of water liquid?
I don't understand the set up.
The setup is like this (answered by bobpursly):
The sum of heats gained =0
80(cice)(0+15)+80Hf+80cw(Tf-0)+250cw(Tf-85)=0
solve for Tfinal Tf
1 answer
what do you not understand? some lose heat (a negative heat gained) and some gain heat, the sum is zero.
1 answer