NH4F + 2H2O ==> NH3(aq) + HF(aq)
Addition of HCl; most of the H^+ is used up by the NH3 to form NH4^+.
Addition of NaOH; mot of the OH^- is used up by the HF.
What is the equilibrium equations that result when solid NH4F is dissolved in sufficient water to produce 5.0 mL of 0.5M NH4F solution?
How would the addition of 5 drops of 0.1M HCl affect the equilibrium system. Give an explanation.
How would the addition of 5 drops of NaOH affect the equilibrium system? Give an explanation.
1 answer