What is the equation of the line that passes through the point(−2,−4) and has a slope of 1/2?

Answer 1

To find the equation of the line, we can use the point-slope form, which is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope of the line.

In this case, we are given the point (-2, -4) and a slope of 1/2, so we have:

y - (-4) = (1/2)(x - (-2))

Simplifying the equation:

y + 4 = (1/2)(x + 2)

Multiply both sides by 2 to eliminate the fraction:

2(y + 4) = x + 2

Distribute 2 on the left side:

2y + 8 = x + 2

Rearrange the equation to the standard form:

x - 2y = -6

Therefore, the equation of the line is x - 2y = -6.