Let's denote the average number of widgets made by a person as \( x \).
According to the problem:
- The first worker makes \( 3x \) widgets (3 times the average).
- The second worker makes \( \frac{7}{5} x \) widgets (7/5 times the average).
Now, we want to find how many times more widgets the first worker makes than the second worker. To do this, we can set up the equation:
\[ \text{Ratio} = \frac{\text{Widgets made by first worker}}{\text{Widgets made by second worker}} = \frac{3x}{\frac{7}{5}x} \]
The \( x \) in the numerator and denominator cancels out:
\[ \text{Ratio} = \frac{3}{\frac{7}{5}} = 3 \times \frac{5}{7} = \frac{15}{7} \]
Thus, the first worker makes \( \frac{15}{7} \) times as many widgets as the second worker.
To express how many times more widgets the first worker makes than the second worker, we can subtract 1:
\[ \frac{15}{7} - 1 = \frac{15}{7} - \frac{7}{7} = \frac{8}{7} \]
So, the first worker makes \( \frac{8}{7} \) (or approximately 1.14) times more widgets than the second worker.
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