Let the average number of widgets made by a person be \( x \).
From the problem statement:
- The first worker makes \( 3x \) widgets.
- The second worker makes \( \frac{7}{5}x \) widgets.
To find how many times more widgets the first worker makes than the second worker, we need to divide the number of widgets made by the first worker by the number made by the second worker:
\[ \text{Ratio} = \frac{3x}{\frac{7}{5}x} \]
The \( x \) in the numerator and denominator cancels out:
\[ \text{Ratio} = \frac{3}{\frac{7}{5}} = 3 \times \frac{5}{7} = \frac{15}{7} \]
This means the first worker makes \( \frac{15}{7} \) times as many widgets as the second worker.
Thus, the first worker makes \( \frac{15}{7} \) times more widgets than the second worker.
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