What is the empirical forumla (lowest whole ratio) of the compounds below?

A.

13.0g Mg 1 mole/24.312 = .53 mole
87.0g Br 1 mole/79.909g = 1.09 mole

Mg .53/.53 Br 1.09/.53

Mg 1.0 Br 2.1

What do i do now?

5 answers

I didn't check your math but if it's correct, round the 2.1 to 2.0 and the formula is Mg1Br2.0 or MgBr2.
you just write it as MgBr2
since when is 2.054 rounded up .

Round it to the nearest whole number
MgBr2
My teacher told me what I needed to get both numbers to whole numbers by mutiplying 2-6. But i do not know when to do it. Can you please give me an example
http://books.google.com/books?id=EKOBuCwHh9wC&pg=PA29&lpg=PA29&dq=empirical+formula+C3H8&source=web&ots=2XWO2gHpDo&sig=CQMIhjMo-rkgb0Quz5KGGpXXQMs&hl=en&sa=X&oi=book_result&resnum=3&ct=result#PPA30,M1

See prob 3-2, where they had to multipy by 2 to get a whole number ratio
Similar Questions
  1. This is kind of tricky for me.What os the empirical formula (lowest whole number ratio) of the compounds below? A. 25.3% Cu,
    1. answers icon 6 answers
  2. Two compounds that contain Cu and Cl have the following masses:Cpd A: 32.10 g Cu and 17.90 g Cl Cpd B: 23.64 g Cu and 26.37 g Cl
    1. answers icon 2 answers
    1. answers icon 0 answers
    1. answers icon 3 answers
more similar questions