What is the empirical formula of a compound that contains 27.0%S, 13.4%O,and 59.6%Cl by mass?

Answer 1

Take a 100 g sample which will give you
27.0g S
13.4 g O and
59.6g Cl

Now convert grams to moles. moles = grams/molar mass

Then find the molar ratio of the elements to each other with the smallest number being 1.00. You can do that easily by dividing the smallest number by itself and you know that one will be 1.00. Then divide the other numbers by the same small number. Finally round to the nearest whole number and formula will be
SxOyClz where x,y, and z are the mole ratios.
Post your work if you get stuck.

Answer 2

give the answer asswhole