what is the empirical formula for a compund with 26.2 g N, 7.5 g H, and 66.3 g Cl?

Answer 1

26.2 g of N*(1 mole of N/14.01g)= moles of N=1.87 moles of N

7.5 g of H *(1 mole of H/1.007 g of H)= moles of H=7.45 moles of H

66.3 g of Cl *(1 mole of Cl/35.45g of Cl)= moles of Cl=1.87 moles of Cl

take the lowest number of moles, and divide by the others.

N=1.87/1.87=1
H=7.45/1.87=3.98=4
Cl=1.87/1.87=1